Base | Representation |
---|---|
bin | 100011010111000100000101… |
… | …0001010010010110001001000 |
3 | 1111210021110211100212211220110 |
4 | 1012232020022022102301020 |
5 | 311231431303200042300 |
6 | 3021302350015154320 |
7 | 122341254320164602 |
oct | 10656101212226110 |
9 | 1453243740784813 |
10 | 311033112112200 |
11 | 90117447197415 |
12 | 2aa74373b159a0 |
13 | 104723b189a06a |
14 | 56b4123884172 |
15 | 25e5a41e7e550 |
hex | 11ae20a292c48 |
311033112112200 has 48 divisors (see below), whose sum is σ = 964202647549680. Its totient is φ = 82942163229760.
The previous prime is 311033112112157. The next prime is 311033112112207. The reversal of 311033112112200 is 2211211330113.
It is not an unprimeable number, because it can be changed into a prime (311033112112207) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 259194259494 + ... + 259194260693.
It is an arithmetic number, because the mean of its divisors is an integer number (20087555157285).
Almost surely, 2311033112112200 is an apocalyptic number.
311033112112200 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
311033112112200 is an abundant number, since it is smaller than the sum of its proper divisors (653169535437480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311033112112200 is a wasteful number, since it uses less digits than its factorization.
311033112112200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 518388520206 (or 518388520197 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 311033112112200 its reverse (2211211330113), we get a palindrome (313244323442313).
The spelling of 311033112112200 in words is "three hundred eleven trillion, thirty-three billion, one hundred twelve million, one hundred twelve thousand, two hundred".
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