Base | Representation |
---|---|
bin | 101101010010011000110… |
… | …100011011000001010101 |
3 | 102000111221000012122020022 |
4 | 231102120310123001111 |
5 | 401442110232420201 |
6 | 10341404400314525 |
7 | 440562145146326 |
oct | 55223064330125 |
9 | 12014830178208 |
10 | 3112120201301 |
11 | a9a92a7a2471 |
12 | 423196912a45 |
13 | 19761936b897 |
14 | aa8ad90444d |
15 | 55e47a4441b |
hex | 2d498d1b055 |
3112120201301 has 2 divisors, whose sum is σ = 3112120201302. Its totient is φ = 3112120201300.
The previous prime is 3112120201297. The next prime is 3112120201303. The reversal of 3112120201301 is 1031020212113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2485822069201 + 626298132100 = 1576649^2 + 791390^2 .
It is an emirp because it is prime and its reverse (1031020212113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3112120201301 - 22 = 3112120201297 is a prime.
Together with 3112120201303, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3112120201301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3112120201303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556060100650 + 1556060100651.
It is an arithmetic number, because the mean of its divisors is an integer number (1556060100651).
Almost surely, 23112120201301 is an apocalyptic number.
It is an amenable number.
3112120201301 is a deficient number, since it is larger than the sum of its proper divisors (1).
3112120201301 is an equidigital number, since it uses as much as digits as its factorization.
3112120201301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 3112120201301 its reverse (1031020212113), we get a palindrome (4143140413414).
The spelling of 3112120201301 in words is "three trillion, one hundred twelve billion, one hundred twenty million, two hundred one thousand, three hundred one".
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