Base | Representation |
---|---|
bin | 1110001001110101110010… |
… | …10000011010001100111011 |
3 | 11002012110121211000201202012 |
4 | 13010322321100122030323 |
5 | 13034420323411112103 |
6 | 150110212034400135 |
7 | 6361444444222151 |
oct | 704727120321473 |
9 | 132173554021665 |
10 | 31124441113403 |
11 | 9a0a88a661320 |
12 | 35a816043004b |
13 | 144a039a1b6b1 |
14 | 7986068b73d1 |
15 | 38e9413512d8 |
hex | 1c4eb941a33b |
31124441113403 has 64 divisors (see below), whose sum is σ = 37638604523520. Its totient is φ = 25410010214400.
The previous prime is 31124441113397. The next prime is 31124441113453. The reversal of 31124441113403 is 30431114442113.
It is a happy number.
It is not a de Polignac number, because 31124441113403 - 222 = 31124436919099 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31124441113403.
It is not an unprimeable number, because it can be changed into a prime (31124441113453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 514908500 + ... + 514968942.
It is an arithmetic number, because the mean of its divisors is an integer number (588103195680).
Almost surely, 231124441113403 is an apocalyptic number.
31124441113403 is a deficient number, since it is larger than the sum of its proper divisors (6514163410117).
31124441113403 is a wasteful number, since it uses less digits than its factorization.
31124441113403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61988.
The product of its (nonzero) digits is 13824, while the sum is 32.
Adding to 31124441113403 its reverse (30431114442113), we get a palindrome (61555555555516).
The spelling of 31124441113403 in words is "thirty-one trillion, one hundred twenty-four billion, four hundred forty-one million, one hundred thirteen thousand, four hundred three".
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