Base | Representation |
---|---|
bin | 1110001010000011110111… |
… | …10011011000110100110000 |
3 | 11002020012010121110110222011 |
4 | 13011001323303120310300 |
5 | 13040031314001430000 |
6 | 150113502100252304 |
7 | 6362132661030652 |
oct | 705017363306460 |
9 | 132205117413864 |
10 | 31132000030000 |
11 | 9a13009453231 |
12 | 35a970b9a1094 |
13 | 144a972a674cc |
14 | 798b227646d2 |
15 | 38ec34c702ba |
hex | 1c507bcd8d30 |
31132000030000 has 50 divisors (see below), whose sum is σ = 75373685296844. Its totient is φ = 12452800008000.
The previous prime is 31132000029997. The next prime is 31132000030051. The reversal of 31132000030000 is 3000023113.
It is a tau number, because it is divible by the number of its divisors (50).
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 1556590002 + ... + 1556610001.
Almost surely, 231132000030000 is an apocalyptic number.
It is an amenable number.
31132000030000 is an abundant number, since it is smaller than the sum of its proper divisors (44241685266844).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31132000030000 is an equidigital number, since it uses as much as digits as its factorization.
31132000030000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3113200031 (or 3113200010 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 13.
Adding to 31132000030000 its reverse (3000023113), we get a palindrome (31135000053113).
The spelling of 31132000030000 in words is "thirty-one trillion, one hundred thirty-two billion, thirty thousand".
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