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31133012300000 = 25551340575903
BaseRepresentation
bin1110001010000101110000…
…01000111001000011100000
311002020021202011020010100122
413011002320020321003200
513040040402122100000
6150114150340535412
76362200032134312
oct705027010710340
9132207664203318
1031133012300000
119a13488897706
1235a99529b1568
13144aaa46ac540
14798bbad877b2
1538ec93a77085
hex1c50b82390e0

31133012300000 has 288 divisors, whose sum is σ = 82539002415744. Its totient is φ = 11490485760000.

The previous prime is 31133012299999. The next prime is 31133012300021. The reversal of 31133012300000 is 321033113.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5274097049 + ... + 5274102951.

It is an arithmetic number, because the mean of its divisors is an integer number (286593758388).

Almost surely, 231133012300000 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31133012300000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (41269501207872).

31133012300000 is an abundant number, since it is smaller than the sum of its proper divisors (51405990115744).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31133012300000 is an equidigital number, since it uses as much as digits as its factorization.

31133012300000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10008 (or 9980 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 31133012300000 its reverse (321033113), we get a palindrome (31133333333113).

The spelling of 31133012300000 in words is "thirty-one trillion, one hundred thirty-three billion, twelve million, three hundred thousand".