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311412100120 = 235113291011997
BaseRepresentation
bin1001000100000011001…
…10111000110000011000
31002202210211210210001221
410202001212320300120
520100232444200440
6355021042021424
731333040114302
oct4420146706030
91082724723057
10311412100120
11110084015000
125042b347874
132349b243284
1411102a46972
158179501d4a
hex48819b8c18

311412100120 has 256 divisors, whose sum is σ = 805564828800. Its totient is φ = 108199168000.

The previous prime is 311412100117. The next prime is 311412100147. The reversal of 311412100120 is 21001214113.

It is a super-2 number, since 2×3114121001202 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 311412100094 and 311412100103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 155938962 + ... + 155940958.

Almost surely, 2311412100120 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 311412100120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (402782414400).

311412100120 is an abundant number, since it is smaller than the sum of its proper divisors (494152728680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311412100120 is a wasteful number, since it uses less digits than its factorization.

311412100120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2171 (or 2145 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 311412100120 its reverse (21001214113), we get a palindrome (332413314233).

The spelling of 311412100120 in words is "three hundred eleven billion, four hundred twelve million, one hundred thousand, one hundred twenty".