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311420343310 = 2531142034331
BaseRepresentation
bin1001000100000100001…
…10010101010000001110
31002202211102022120121021
410202002012111100032
520100242101441220
6355021534424354
731333200146026
oct4420206252016
91082742276537
10311420343310
1111008873525a
12504320620ba
132349cb6b2bb
1411103b90a86
15817a0ce4aa
hex488219540e

311420343310 has 8 divisors (see below), whose sum is σ = 560556617976. Its totient is φ = 124568137320.

The previous prime is 311420343251. The next prime is 311420343317. The reversal of 311420343310 is 13343024113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×3114203433102 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311420343317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15571017156 + ... + 15571017175.

It is an arithmetic number, because the mean of its divisors is an integer number (70069577247).

Almost surely, 2311420343310 is an apocalyptic number.

311420343310 is a deficient number, since it is larger than the sum of its proper divisors (249136274666).

311420343310 is a wasteful number, since it uses less digits than its factorization.

311420343310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31142034338.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 311420343310 its reverse (13343024113), we get a palindrome (324763367423).

It can be divided in two parts, 3114203 and 43310, that added together give a palindrome (3157513).

The spelling of 311420343310 in words is "three hundred eleven billion, four hundred twenty million, three hundred forty-three thousand, three hundred ten".

Divisors: 1 2 5 10 31142034331 62284068662 155710171655 311420343310