Base | Representation |
---|---|
bin | 100011011001111100111001… |
… | …0100001011100000100010100 |
3 | 1111211200102021011110121022121 |
4 | 1012303321302201130010110 |
5 | 311304432120000020200 |
6 | 3022204544504105324 |
7 | 122412034502450155 |
oct | 10663716241340424 |
9 | 1454612234417277 |
10 | 311430000001300 |
11 | 9025a7a3045834 |
12 | 2ab19278a65244 |
13 | 104a095252ca5b |
14 | 56c94145b992c |
15 | 260102053ae1a |
hex | 11b3e7285c114 |
311430000001300 has 72 divisors (see below), whose sum is σ = 697658753926400. Its totient is φ = 120543948057600.
The previous prime is 311430000001283. The next prime is 311430000001313. The reversal of 311430000001300 is 3100000034113.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 34994851 + ... + 42982549.
Almost surely, 2311430000001300 is an apocalyptic number.
It is an amenable number.
311430000001300 is an abundant number, since it is smaller than the sum of its proper divisors (386228753925100).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311430000001300 is a wasteful number, since it uses less digits than its factorization.
311430000001300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8000321 (or 8000314 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 311430000001300 its reverse (3100000034113), we get a palindrome (314530000035413).
The spelling of 311430000001300 in words is "three hundred eleven trillion, four hundred thirty billion, one thousand, three hundred".
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