311430034113133 has 8 divisors (see below), whose sum is σ = 353038095351200. Its totient is φ = 272343673556208.

The previous prime is 311430034113097. The next prime is 311430034113257. The reversal of 311430034113133 is 331311430034113.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 311430034113133 - 2²¹ = 311430032015981 is a prime.

It is a super-4 number, since 4×311430034113133⁴ (a number of 59 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311430034113095 and 311430034113104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311430034110133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 630425170023 + ... + 630425170516.

It is an arithmetic number, because the mean of its divisors is an integer number (44129761918900).

Almost surely, 2^{311430034113133} is an apocalyptic number.

It is an amenable number.

311430034113133 is a deficient number, since it is larger than the sum of its proper divisors (41608061238067).

311430034113133 is a wasteful number, since it uses less digits than its factorization.

311430034113133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1260850340571.

The product of its (nonzero) digits is 11664, while the sum is 31.

Adding to 311430034113133 its reverse (331311430034113), we get a palindrome (642741464147246).

The spelling of 311430034113133 in words is "three hundred eleven trillion, four hundred thirty billion, thirty-four million, one hundred thirteen thousand, one hundred thirty-three".