Base | Representation |
---|---|
bin | 11101000000010010… |
… | …010011011111000111 |
3 | 2222101102122010122012 |
4 | 131000102103133013 |
5 | 1002240141430203 |
6 | 22150153124435 |
7 | 2151521530646 |
oct | 350022233707 |
9 | 88342563565 |
10 | 31143311303 |
11 | 12231650805 |
12 | 60519b971b |
13 | 2c241cb870 |
14 | 171621d35d |
15 | c241b7bd8 |
hex | 7404937c7 |
31143311303 has 4 divisors (see below), whose sum is σ = 33538950648. Its totient is φ = 28747671960.
The previous prime is 31143311273. The next prime is 31143311327. The reversal of 31143311303 is 30311334113.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30311334113 = 479 ⋅63280447.
It is a cyclic number.
It is not a de Polignac number, because 31143311303 - 212 = 31143307207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31143311333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1197819653 + ... + 1197819678.
It is an arithmetic number, because the mean of its divisors is an integer number (8384737662).
Almost surely, 231143311303 is an apocalyptic number.
31143311303 is a deficient number, since it is larger than the sum of its proper divisors (2395639345).
31143311303 is a wasteful number, since it uses less digits than its factorization.
31143311303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2395639344.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 31143311303 its reverse (30311334113), we get a palindrome (61454645416).
The spelling of 31143311303 in words is "thirty-one billion, one hundred forty-three million, three hundred eleven thousand, three hundred three".
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