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312020031133140 = 2235111728019928337
BaseRepresentation
bin100011011110001111101001…
…1000111100101010111010100
31111220202211020110010200112120
41012330133103013211113110
5311344114010432230030
63023340005023015540
7122502463146354501
oct10674372307452724
91456684213120476
10312020031133140
1190467a52258110
122abb36a513a5b0
1310514493a7ccb5
145709bc88c24a8
1526115550ea010
hex11bc7d31e55d4

312020031133140 has 192 divisors, whose sum is σ = 1009503241221888. Its totient is φ = 71166312448000.

The previous prime is 312020031133081. The next prime is 312020031133147. The reversal of 312020031133140 is 41331130020213.

It is a self number, because there is not a number n which added to its sum of digits gives 312020031133140.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312020031133147) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 26463052 + ... + 36391388.

It is an arithmetic number, because the mean of its divisors is an integer number (5257829381364).

Almost surely, 2312020031133140 is an apocalyptic number.

312020031133140 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 312020031133140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (504751620610944).

312020031133140 is an abundant number, since it is smaller than the sum of its proper divisors (697483210088748).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

312020031133140 is a wasteful number, since it uses less digits than its factorization.

312020031133140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9931178 (or 9931176 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 312020031133140 its reverse (41331130020213), we get a palindrome (353351161153353).

The spelling of 312020031133140 in words is "three hundred twelve trillion, twenty billion, thirty-one million, one hundred thirty-three thousand, one hundred forty".