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31211312101232 = 241950707006327
BaseRepresentation
bin1110001100010111100110…
…01010111011011101110000
311002111202212000010011002212
413012023303022323131300
513042331231344214412
6150214140121231252
76400641260355224
oct706136312733560
9132452760104085
1031211312101232
119a4370900523a
123600b65332528
1314552a24c8483
1479c8c7dc8784
15391d27b53222
hex1c62f32bb770

31211312101232 has 10 divisors (see below), whose sum is σ = 60471917196168. Its totient is φ = 15605656050608.

The previous prime is 31211312101217. The next prime is 31211312101243. The reversal of 31211312101232 is 23210121311213.

It is a happy number.

It is a super-2 number, since 2×312113121012322 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31211312101198 and 31211312101207.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 975353503148 + ... + 975353503179.

Almost surely, 231211312101232 is an apocalyptic number.

It is an amenable number.

31211312101232 is a deficient number, since it is larger than the sum of its proper divisors (29260605094936).

31211312101232 is a wasteful number, since it uses less digits than its factorization.

31211312101232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1950707006335 (or 1950707006329 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 31211312101232 its reverse (23210121311213), we get a palindrome (54421433412445).

The spelling of 31211312101232 in words is "thirty-one trillion, two hundred eleven billion, three hundred twelve million, one hundred one thousand, two hundred thirty-two".

Divisors: 1 2 4 8 16 1950707006327 3901414012654 7802828025308 15605656050616 31211312101232