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31212112113000 = 233253713101377327
BaseRepresentation
bin1110001100011001000101…
…10110101110110101101000
311002111211220202110221221100
413012030202312232311220
513042334401200104000
6150214351340241400
76401000143351110
oct706144266566550
9132454822427840
1031212112113000
119a43a89653995
123601149240260
13145539c183810
1479c962358040
15391d72ecda00
hex1c6322daed68

31212112113000 has 768 divisors, whose sum is σ = 131128302090240. Its totient is φ = 6520193280000.

The previous prime is 31212112112969. The next prime is 31212112113019. The reversal of 31212112113000 is 31121121213.

31212112113000 is a `hidden beast` number, since 31 + 2 + 121 + 1 + 211 + 300 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 82530337 + ... + 82907663.

It is an arithmetic number, because the mean of its divisors is an integer number (170739976680).

Almost surely, 231212112113000 is an apocalyptic number.

31212112113000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31212112113000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (65564151045120).

31212112113000 is an abundant number, since it is smaller than the sum of its proper divisors (99916189977240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31212112113000 is a wasteful number, since it uses less digits than its factorization.

31212112113000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 377475 (or 377458 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 31212112113000 its reverse (31121121213), we get a palindrome (31243233234213).

The spelling of 31212112113000 in words is "thirty-one trillion, two hundred twelve billion, one hundred twelve million, one hundred thirteen thousand".