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31231200000000 = 211358711132
BaseRepresentation
bin1110001100111100101001…
…00101001111100000000000
311002120200012000201002101010
413012132110211033200000
513043142444200000000
6150231225404040520
76402244151616330
oct706362445174000
9132520160632333
1031231200000000
119a51094227a10
123604995833140
1314571218b3500
1479d85344d0c0
153925ddb28d50
hex1c679494f800

31231200000000 has 2592 divisors, whose sum is σ = 140509615559040. Its totient is φ = 5990400000000.

The previous prime is 31231199999981. The next prime is 31231200000031. The reversal of 31231200000000 is 213213.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 2402399999994 + ... + 2402400000006.

It is an arithmetic number, because the mean of its divisors is an integer number (54208956620).

Almost surely, 231231200000000 is an apocalyptic number.

31231200000000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31231200000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (70254807779520).

31231200000000 is an abundant number, since it is smaller than the sum of its proper divisors (109278415559040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31231200000000 is an frugal number, since it uses more digits than its factorization.

31231200000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 109 (or 41 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 12.

Adding to 31231200000000 its reverse (213213), we get a palindrome (31231200213213).

It can be divided in two parts, 312 and 31200000000, that multiplied together give a square (9734400000000 = 31200002).

The spelling of 31231200000000 in words is "thirty-one trillion, two hundred thirty-one billion, two hundred million", and thus it is an aban number.