Base | Representation |
---|---|
bin | 1001001010111100000… |
… | …10111100010010000011 |
3 | 1010010100120220000112101 |
4 | 10211132002330102003 |
5 | 20130321233121430 |
6 | 400432034211231 |
7 | 31523505364420 |
oct | 4453602742203 |
9 | 1103316800471 |
10 | 315110442115 |
11 | 1117016a2097 |
12 | 510a1a23b17 |
13 | 2393a506311 |
14 | 11373cb4d47 |
15 | 82e403bdca |
hex | 495e0bc483 |
315110442115 has 32 divisors (see below), whose sum is σ = 450987780096. Its totient is φ = 206659537920.
The previous prime is 315110442091. The next prime is 315110442139. The reversal of 315110442115 is 511244011513.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (315110442091) and next prime (315110442139).
It is not a de Polignac number, because 315110442115 - 219 = 315109917827 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12280339 + ... + 12305971.
It is an arithmetic number, because the mean of its divisors is an integer number (14093368128).
Almost surely, 2315110442115 is an apocalyptic number.
315110442115 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
315110442115 is a deficient number, since it is larger than the sum of its proper divisors (135877337981).
315110442115 is a wasteful number, since it uses less digits than its factorization.
315110442115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40939.
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 315110442115 its reverse (511244011513), we get a palindrome (826354453628).
The spelling of 315110442115 in words is "three hundred fifteen billion, one hundred ten million, four hundred forty-two thousand, one hundred fifteen".
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