Base | Representation |
---|---|
bin | 11101010111111100… |
… | …101100100100010111 |
3 | 10000102002122020211022 |
4 | 131113330230210113 |
5 | 1004043304100210 |
6 | 22253414031355 |
7 | 2164412061365 |
oct | 352774544427 |
9 | 100362566738 |
10 | 31540300055 |
11 | 1241574a290 |
12 | 614294855b |
13 | 2c88527654 |
14 | 1752c3c635 |
15 | c48e84155 |
hex | 757f2c917 |
31540300055 has 8 divisors (see below), whose sum is σ = 41289120144. Its totient is φ = 22938400000.
The previous prime is 31540300027. The next prime is 31540300069. The reversal of 31540300055 is 55000304513.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 31540300055 - 218 = 31540037911 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 31540299997 and 31540300033.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 286729946 + ... + 286730055.
It is an arithmetic number, because the mean of its divisors is an integer number (5161140018).
Almost surely, 231540300055 is an apocalyptic number.
31540300055 is a deficient number, since it is larger than the sum of its proper divisors (9748820089).
31540300055 is a wasteful number, since it uses less digits than its factorization.
31540300055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 573460017.
The product of its (nonzero) digits is 4500, while the sum is 26.
Adding to 31540300055 its reverse (55000304513), we get a palindrome (86540604568).
The spelling of 31540300055 in words is "thirty-one billion, five hundred forty million, three hundred thousand, fifty-five".
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