3160111401300 has 144 divisors (see below), whose sum is σ = 10999405437440. Its totient is φ = 684294791040.

The previous prime is 3160111401197. The next prime is 3160111401331. The reversal of 3160111401300 is 31041110613.

3160111401300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 39560494 + ... + 39640293.

Almost surely, 2^{3160111401300} is an apocalyptic number.

3160111401300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

3160111401300 is an abundant number, since it is smaller than the sum of its proper divisors (7839294036140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3160111401300 is a wasteful number, since it uses less digits than its factorization.

3160111401300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79200830 (or 79200823 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 3160111401300 its reverse (31041110613), we get a palindrome (3191152511913).

The spelling of 3160111401300 in words is "three trillion, one hundred sixty billion, one hundred eleven million, four hundred one thousand, three hundred".