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32101212000000 = 28356111321439
BaseRepresentation
bin1110100110010001001010…
…10101101000111100000000
311012122211211122202221010210
413103020211111220330000
513201421240233000000
6152135032044354120
76522143646610413
oct723104525507400
9135584748687123
1032101212000000
11a25705832a530
12372551ab45940
1314bb192619500
147cd9c7c31b7a
153aa05d5ec350
hex1d3225568f00

32101212000000 has 1512 divisors, whose sum is σ = 126240934095360. Its totient is φ = 7178496000000.

The previous prime is 32101211999993. The next prime is 32101212000017. The reversal of 32101212000000 is 21210123.

32101212000000 is digitally balanced in base 6, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a self number, because there is not a number n which added to its sum of digits gives 32101212000000.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 167 ways as a sum of consecutive naturals, for example, 22307999281 + ... + 22308000719.

It is an arithmetic number, because the mean of its divisors is an integer number (83492681280).

Almost surely, 232101212000000 is an apocalyptic number.

32101212000000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 32101212000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (63120467047680).

32101212000000 is an abundant number, since it is smaller than the sum of its proper divisors (94139722095360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

32101212000000 is an equidigital number, since it uses as much as digits as its factorization.

32101212000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1525 (or 1473 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 32101212000000 its reverse (21210123), we get a palindrome (32101233210123).

The spelling of 32101212000000 in words is "thirty-two trillion, one hundred one billion, two hundred twelve million", and thus it is an aban number.