Base | Representation |
---|---|
bin | 1110100110101001000100… |
… | …00001001010001010010100 |
3 | 11012201001221202011212211111 |
4 | 13103110202001022022110 |
5 | 13202124024021420200 |
6 | 152144553054544404 |
7 | 6523106610201562 |
oct | 723244201121224 |
9 | 135631852155744 |
10 | 32114041201300 |
11 | a261541057333 |
12 | 3727abb508104 |
13 | 14bc4584b9496 |
14 | 7d0483a1aa32 |
15 | 3aa55ea620ba |
hex | 1d352204a294 |
32114041201300 has 36 divisors (see below), whose sum is σ = 69706350584416. Its totient is φ = 12842136079200.
The previous prime is 32114041201259. The next prime is 32114041201309. The reversal of 32114041201300 is 310214041123.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32114041201309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 43134072 + ... + 43872271.
Almost surely, 232114041201300 is an apocalyptic number.
It is an amenable number.
32114041201300 is an abundant number, since it is smaller than the sum of its proper divisors (37592309383116).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
32114041201300 is a wasteful number, since it uses less digits than its factorization.
32114041201300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 87010048 (or 87010041 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 32114041201300 its reverse (310214041123), we get a palindrome (32424255242423).
The spelling of 32114041201300 in words is "thirty-two trillion, one hundred fourteen billion, forty-one million, two hundred one thousand, three hundred".
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