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321141311 is a prime number
BaseRepresentation
bin10011001001000…
…011101000111111
3211101021200001122
4103021003220333
51124203010221
651511101155
710646441021
oct2311035077
9741250048
10321141311
11155304247
128b6717bb
13516c085a
1430918011
151d2d7eab
hex13243a3f

321141311 has 2 divisors, whose sum is σ = 321141312. Its totient is φ = 321141310.

The previous prime is 321141283. The next prime is 321141313. The reversal of 321141311 is 113141123.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-321141311 is a prime.

It is a Sophie Germain prime.

Together with 321141313, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 321141311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (321141313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160570655 + 160570656.

It is an arithmetic number, because the mean of its divisors is an integer number (160570656).

Almost surely, 2321141311 is an apocalyptic number.

321141311 is a deficient number, since it is larger than the sum of its proper divisors (1).

321141311 is an equidigital number, since it uses as much as digits as its factorization.

321141311 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 72, while the sum is 17.

The square root of 321141311 is about 17920.4160386973. The cubic root of 321141311 is about 684.8025864777.

Adding to 321141311 its reverse (113141123), we get a palindrome (434282434).

The spelling of 321141311 in words is "three hundred twenty-one million, one hundred forty-one thousand, three hundred eleven".