Base | Representation |
---|---|
bin | 1110100110110110110011… |
… | …11001000000111010010100 |
3 | 11012201210000001122121010220 |
4 | 13103123121321000322110 |
5 | 13202234132241310200 |
6 | 152152213242314340 |
7 | 6523460520616233 |
oct | 723333171007224 |
9 | 135653001577126 |
10 | 32121421041300 |
11 | a264688857358 |
12 | 372941aab89b0 |
13 | 14c00633c5806 |
14 | 7d0983bb0b1a |
15 | 3aa8428ab4a0 |
hex | 1d36d9e40e94 |
32121421041300 has 144 divisors (see below), whose sum is σ = 95943997857792. Its totient is φ = 8288705980800.
The previous prime is 32121421041277. The next prime is 32121421041323. The reversal of 32121421041300 is 314012412123.
It is an interprime number because it is at equal distance from previous prime (32121421041277) and next prime (32121421041323).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 116139777 + ... + 116416023.
Almost surely, 232121421041300 is an apocalyptic number.
32121421041300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 32121421041300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (47971998928896).
32121421041300 is an abundant number, since it is smaller than the sum of its proper divisors (63822576816492).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
32121421041300 is a wasteful number, since it uses less digits than its factorization.
32121421041300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 288798 (or 288791 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 32121421041300 its reverse (314012412123), we get a palindrome (32435433453423).
The spelling of 32121421041300 in words is "thirty-two trillion, one hundred twenty-one billion, four hundred twenty-one million, forty-one thousand, three hundred".
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