Search a number
-
+
321231000119 is a prime number
BaseRepresentation
bin1001010110010101101…
…11000001001000110111
31010201011010210120200212
410223022313001020313
520230340114000434
6403323235100035
732131255310021
oct4531267011067
91121133716625
10321231000119
11114262585997
125230b74161b
13243a4562c83
1411794b07011
15855153a8ce
hex4acadc1237

321231000119 has 2 divisors, whose sum is σ = 321231000120. Its totient is φ = 321231000118.

The previous prime is 321231000091. The next prime is 321231000121. The reversal of 321231000119 is 911000132123.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 321231000119 - 220 = 321229951543 is a prime.

It is a super-2 number, since 2×3212310001192 (a number of 24 digits) contains 22 as substring.

Together with 321231000121, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 321231000094 and 321231000103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (321231000149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160615500059 + 160615500060.

It is an arithmetic number, because the mean of its divisors is an integer number (160615500060).

Almost surely, 2321231000119 is an apocalyptic number.

321231000119 is a deficient number, since it is larger than the sum of its proper divisors (1).

321231000119 is an equidigital number, since it uses as much as digits as its factorization.

321231000119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 23.

The spelling of 321231000119 in words is "three hundred twenty-one billion, two hundred thirty-one million, one hundred nineteen", and thus it is an aban number.