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322421117 is a prime number
BaseRepresentation
bin10011001101111…
…100000101111101
3211110200200121212
4103031330011331
51130014433432
651554334205
710663351154
oct2315740575
9743620555
10322421117
11155aa8837
128bb8a365
1351a4b235
1430b6c59b
151d48c2b2
hex1337c17d

322421117 has 2 divisors, whose sum is σ = 322421118. Its totient is φ = 322421116.

The previous prime is 322421083. The next prime is 322421119. The reversal of 322421117 is 711124223.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 225870841 + 96550276 = 15029^2 + 9826^2 .

It is an emirp because it is prime and its reverse (711124223) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-322421117 is a prime.

Together with 322421119, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 322421092 and 322421101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (322421119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161210558 + 161210559.

It is an arithmetic number, because the mean of its divisors is an integer number (161210559).

Almost surely, 2322421117 is an apocalyptic number.

It is an amenable number.

322421117 is a deficient number, since it is larger than the sum of its proper divisors (1).

322421117 is an equidigital number, since it uses as much as digits as its factorization.

322421117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 672, while the sum is 23.

The square root of 322421117 is about 17956.0885774157. The cubic root of 322421117 is about 685.7110679640.

The spelling of 322421117 in words is "three hundred twenty-two million, four hundred twenty-one thousand, one hundred seventeen".