Base | Representation |
---|---|
bin | 100100111101100100010011… |
… | …1110111000010100101011110 |
3 | 1120122011021101200101202100120 |
4 | 1021323020213313002211132 |
5 | 320103241004344100132 |
6 | 3111250323422535410 |
7 | 125324140006655112 |
oct | 11173104767024536 |
9 | 1518137350352316 |
10 | 325121103112542 |
11 | 946590a38a99a0 |
12 | 3056a793737566 |
13 | 10c54a33367789 |
14 | 5a3dd34091742 |
15 | 278c22cb6a02c |
hex | 127b227dc295e |
325121103112542 has 128 divisors (see below), whose sum is σ = 751540284937728. Its totient is φ = 92669587660800.
The previous prime is 325121103112511. The next prime is 325121103112579. The reversal of 325121103112542 is 245211301121523.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 22061545398 + ... + 22061560134.
It is an arithmetic number, because the mean of its divisors is an integer number (5871408476076).
Almost surely, 2325121103112542 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 325121103112542, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (375770142468864).
325121103112542 is an abundant number, since it is smaller than the sum of its proper divisors (426419181825186).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
325121103112542 is a wasteful number, since it uses less digits than its factorization.
325121103112542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25434.
The product of its (nonzero) digits is 14400, while the sum is 33.
The spelling of 325121103112542 in words is "three hundred twenty-five trillion, one hundred twenty-one billion, one hundred three million, one hundred twelve thousand, five hundred forty-two".
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