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332112000000 = 210356111737
BaseRepresentation
bin1001101010100110110…
…10101111010000000000
31011202020110022122110110
410311103122233100000
520420131133000000
6412323052431320
732665021264524
oct4652332572000
91152213278413
10332112000000
11118936625180
1254447778540
1325419923841
1412107c7bd84
15898b920850
hex4d536af400

332112000000 has 1232 divisors, whose sum is σ = 1312621948224. Its totient is φ = 73728000000.

The previous prime is 332111999977. The next prime is 332112000001. The reversal of 332112000000 is 211233.

It is a happy number.

It is a super-2 number, since 2×3321120000002 (a number of 24 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a self number, because there is not a number n which added to its sum of digits gives 332112000000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (332112000001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 8975999982 + ... + 8976000018.

Almost surely, 2332112000000 is an apocalyptic number.

332112000000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 332112000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (656310974112).

332112000000 is an abundant number, since it is smaller than the sum of its proper divisors (980509948224).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

332112000000 is an equidigital number, since it uses as much as digits as its factorization.

332112000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 118 (or 75 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 12.

Adding to 332112000000 its reverse (211233), we get a palindrome (332112211233).

It can be divided in two parts, 33 and 2112000000, that multiplied together give a square (69696000000 = 2640002).

The spelling of 332112000000 in words is "three hundred thirty-two billion, one hundred twelve million", and thus it is an aban number.