Base | Representation |
---|---|
bin | 110000011110011011101… |
… | …010101000110100100010 |
3 | 102210110102211202121222010 |
4 | 300132123222220310202 |
5 | 414034310043101010 |
6 | 11030200511053350 |
7 | 462446343566520 |
oct | 60363352506442 |
9 | 12713384677863 |
10 | 3331211300130 |
11 | 1074838a3079a |
12 | 45973bb11256 |
13 | 1b219397362c |
14 | b73352b5310 |
15 | 5b9bc04a620 |
hex | 3079baa8d22 |
3331211300130 has 128 divisors (see below), whose sum is σ = 9675143055360. Its totient is φ = 716583398400.
The previous prime is 3331211300083. The next prime is 3331211300159. The reversal of 3331211300130 is 310031121333.
It is a super-2 number, since 2×33312113001302 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a junction number, because it is equal to n+sod(n) for n = 3331211300097 and 3331211300106.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 106552441 + ... + 106583699.
It is an arithmetic number, because the mean of its divisors is an integer number (75587055120).
Almost surely, 23331211300130 is an apocalyptic number.
3331211300130 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
3331211300130 is an abundant number, since it is smaller than the sum of its proper divisors (6343931755230).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3331211300130 is a wasteful number, since it uses less digits than its factorization.
3331211300130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61144.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 3331211300130 its reverse (310031121333), we get a palindrome (3641242421463).
The spelling of 3331211300130 in words is "three trillion, three hundred thirty-one billion, two hundred eleven million, three hundred thousand, one hundred thirty".
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