3340134132002 has 4 divisors (see below), whose sum is σ = 5010201198006. Its totient is φ = 1670067066000.

The previous prime is 3340134131993. The next prime is 3340134132019. The reversal of 3340134132002 is 2002314310433.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 3339467511241 + 666620761 = 1827421^2 + 25819^2 .

It is a super-2 number, since 2×3340134132002² (a number of 26 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 835033532999 + ... + 835033533002.

Almost surely, 2^{3340134132002} is an apocalyptic number.

3340134132002 is a deficient number, since it is larger than the sum of its proper divisors (1670067066004).

3340134132002 is a wasteful number, since it uses less digits than its factorization.

3340134132002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1670067066003.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 3340134132002 its reverse (2002314310433), we get a palindrome (5342448442435).

The spelling of 3340134132002 in words is "three trillion, three hundred forty billion, one hundred thirty-four million, one hundred thirty-two thousand, two".