Base | Representation |
---|---|
bin | 110001101001101111000… |
… | …001100000010101001111 |
3 | 110002012010210110110000222 |
4 | 301221233001200111033 |
5 | 421400403033323300 |
6 | 11131252022541555 |
7 | 501341123255243 |
oct | 61515701402517 |
9 | 13065123413028 |
10 | 3412066698575 |
11 | 10a605a776337 |
12 | 4713462978bb |
13 | 1b99ab086972 |
14 | bb2058ba423 |
15 | 5db50685785 |
hex | 31a6f06054f |
3412066698575 has 12 divisors (see below), whose sum is σ = 4414917607248. Its totient is φ = 2610972777600.
The previous prime is 3412066698571. The next prime is 3412066698587. The reversal of 3412066698575 is 5758966602143.
It is not a de Polignac number, because 3412066698575 - 22 = 3412066698571 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3412066698571) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2967013946 + ... + 2967015095.
It is an arithmetic number, because the mean of its divisors is an integer number (367909800604).
It is a 2-persistent number, because it is pandigital, and so is 2⋅3412066698575 = 6824133397150, but 3⋅3412066698575 = 10236200095725 is not.
Almost surely, 23412066698575 is an apocalyptic number.
3412066698575 is a deficient number, since it is larger than the sum of its proper divisors (1002850908673).
3412066698575 is a wasteful number, since it uses less digits than its factorization.
3412066698575 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5934029074 (or 5934029069 counting only the distinct ones).
The product of its (nonzero) digits is 65318400, while the sum is 62.
The spelling of 3412066698575 in words is "three trillion, four hundred twelve billion, sixty-six million, six hundred ninety-eight thousand, five hundred seventy-five".
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