Base | Representation |
---|---|
bin | 11111110100101100… |
… | …001111111001011111 |
3 | 10021012100220102101112 |
4 | 133310230033321133 |
5 | 1024440010324411 |
6 | 23410353532235 |
7 | 2316523205666 |
oct | 376454177137 |
9 | 107170812345 |
10 | 34170011231 |
11 | 13545098204 |
12 | 675757407b |
13 | 32b72a0c75 |
14 | 19221b5ddd |
15 | d4ec82b8b |
hex | 7f4b0fe5f |
34170011231 has 2 divisors, whose sum is σ = 34170011232. Its totient is φ = 34170011230.
The previous prime is 34170011219. The next prime is 34170011233. The reversal of 34170011231 is 13211007143.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34170011231 - 26 = 34170011167 is a prime.
It is a super-2 number, since 2×341700112312 (a number of 22 digits) contains 22 as substring.
Together with 34170011233, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 34170011197 and 34170011206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34170011233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17085005615 + 17085005616.
It is an arithmetic number, because the mean of its divisors is an integer number (17085005616).
Almost surely, 234170011231 is an apocalyptic number.
34170011231 is a deficient number, since it is larger than the sum of its proper divisors (1).
34170011231 is an equidigital number, since it uses as much as digits as its factorization.
34170011231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 34170011231 its reverse (13211007143), we get a palindrome (47381018374).
The spelling of 34170011231 in words is "thirty-four billion, one hundred seventy million, eleven thousand, two hundred thirty-one".
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