3500410021 has 2 divisors, whose sum is σ = 3500410022. Its totient is φ = 3500410020.

The previous prime is 3500410019. The next prime is 3500410037. The reversal of 3500410021 is 1200140053.

3500410021 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (3500410037) can be obtained adding 3500410021 to its sum of digits (16).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3319372996 + 181037025 = 57614^2 + 13455^2 .

It is a cyclic number.

It is not a de Polignac number, because 3500410021 - 2¹ = 3500410019 is a prime.

Together with 3500410019, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 3500409977 and 3500410004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3500410061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1750205010 + 1750205011.

It is an arithmetic number, because the mean of its divisors is an integer number (1750205011).

Almost surely, 2^3500410021 is an apocalyptic number.

It is an amenable number.

3500410021 is a deficient number, since it is larger than the sum of its proper divisors (1).

3500410021 is an equidigital number, since it uses as much as digits as its factorization.

3500410021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 3500410021 is about 59164.2630394396. The cubic root of 3500410021 is about 1518.3537724441.

Adding to 3500410021 its reverse (1200140053), we get a palindrome (4700550074).

The spelling of 3500410021 in words is "three billion, five hundred million, four hundred ten thousand, twenty-one".