Base | Representation |
---|---|
bin | 101000010001010111111011… |
… | …0000001001001100011111101 |
3 | 1201110020012120010211012211120 |
4 | 1100202233312001021203331 |
5 | 332412212211114442140 |
6 | 3253215421355541153 |
7 | 134420246106222246 |
oct | 12042576601114375 |
9 | 1643205503735746 |
10 | 354231555234045 |
11 | a296183914a7a5 |
12 | 3389054715a7b9 |
13 | 12286b7a5985b8 |
14 | 6368c82269ccd |
15 | 2ae4597d321d0 |
hex | 1422bf60498fd |
354231555234045 has 64 divisors (see below), whose sum is σ = 603909120545280. Its totient is φ = 176688069009408.
The previous prime is 354231555234017. The next prime is 354231555234127. The reversal of 354231555234045 is 540432555132453.
It is not a de Polignac number, because 354231555234045 - 29 = 354231555233533 is a prime.
It is a super-3 number, since 3×3542315552340453 (a number of 45 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 19972521 + ... + 33277089.
It is an arithmetic number, because the mean of its divisors is an integer number (9436080008520).
Almost surely, 2354231555234045 is an apocalyptic number.
It is an amenable number.
354231555234045 is a deficient number, since it is larger than the sum of its proper divisors (249677565311235).
354231555234045 is a wasteful number, since it uses less digits than its factorization.
354231555234045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13305254.
The product of its (nonzero) digits is 21600000, while the sum is 51.
The spelling of 354231555234045 in words is "three hundred fifty-four trillion, two hundred thirty-one billion, five hundred fifty-five million, two hundred thirty-four thousand, forty-five".
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