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3999424000000 = 2125611131923
BaseRepresentation
bin111010001100110000001…
…111110011000000000000
3112011100012201211212110211
4322030300033303000000
51011011310021000000
612301150544203504
7561643312042612
oct72146017630000
915140181755424
103999424000000
111302167646310
12547147009594
132301b4683b30
14db804a42db2
156e07a62d7ba
hex3a3303f3000

3999424000000 has 1456 divisors, whose sum is σ = 12900659869440. Its totient is φ = 1216512000000.

The previous prime is 3999423999997. The next prime is 3999424000007. The reversal of 3999424000000 is 4249993.

It is a Harshad number since it is a multiple of its sum of digits (40).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3999424000007) by changing a digit.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 173887999989 + ... + 173888000011.

Almost surely, 23999424000000 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3999424000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6450329934720).

3999424000000 is an abundant number, since it is smaller than the sum of its proper divisors (8901235869440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3999424000000 is an equidigital number, since it uses as much as digits as its factorization.

3999424000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 120 (or 73 counting only the distinct ones).

The product of its (nonzero) digits is 69984, while the sum is 40.

Adding to 3999424000000 its reverse (4249993), we get a palindrome (3999428249993).

The spelling of 3999424000000 in words is "three trillion, nine hundred ninety-nine billion, four hundred twenty-four million", and thus it is an aban number.