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40002013311 = 3131025692649
BaseRepresentation
bin100101010000010011…
…100100100001111111
310211020210211211020120
4211100103210201333
51123411003411221
630213205550023
72614200334341
oct452023444177
9124223754216
1040002013311
1115a68103737
127904715313
133a06608a80
141d16973291
151091c835c6
hex9504e487f

40002013311 has 8 divisors (see below), whose sum is σ = 57438788400. Its totient is φ = 24616623552.

The previous prime is 40002013309. The next prime is 40002013351. The reversal of 40002013311 is 11331020004.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 40002013311 - 21 = 40002013309 is a prime.

It is a super-2 number, since 2×400020133112 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40002013351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 512846286 + ... + 512846363.

It is an arithmetic number, because the mean of its divisors is an integer number (7179848550).

Almost surely, 240002013311 is an apocalyptic number.

40002013311 is a deficient number, since it is larger than the sum of its proper divisors (17436775089).

40002013311 is a wasteful number, since it uses less digits than its factorization.

40002013311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1025692665.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 40002013311 its reverse (11331020004), we get a palindrome (51333033315).

The spelling of 40002013311 in words is "forty billion, two million, thirteen thousand, three hundred eleven".

Divisors: 1 3 13 39 1025692649 3077077947 13334004437 40002013311