Base | Representation |
---|---|
bin | 1011101011001010100… |
… | …01011111100111110001 |
3 | 1102100101111211022201220 |
4 | 11311211101133213301 |
5 | 23033004021341223 |
6 | 504135502215253 |
7 | 40660254416250 |
oct | 5654521374761 |
9 | 1370344738656 |
10 | 401131043313 |
11 | 14513401aa40 |
12 | 658a9b84529 |
13 | 2ba98a6ab40 |
14 | 155b44a2797 |
15 | a67ad626e3 |
hex | 5d6545f9f1 |
401131043313 has 64 divisors (see below), whose sum is σ = 737517268992. Its totient is φ = 187151834880.
The previous prime is 401131043311. The next prime is 401131043317. The reversal of 401131043313 is 313340131104.
It is not a de Polignac number, because 401131043313 - 21 = 401131043311 is a prime.
It is a super-3 number, since 3×4011310433133 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (401131043311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1693981 + ... + 1916202.
It is an arithmetic number, because the mean of its divisors is an integer number (11523707328).
Almost surely, 2401131043313 is an apocalyptic number.
It is an amenable number.
401131043313 is a deficient number, since it is larger than the sum of its proper divisors (336386225679).
401131043313 is a wasteful number, since it uses less digits than its factorization.
401131043313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3610254.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 401131043313 its reverse (313340131104), we get a palindrome (714471174417).
The spelling of 401131043313 in words is "four hundred one billion, one hundred thirty-one million, forty-three thousand, three hundred thirteen".
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