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40130040500 = 22531129311809
BaseRepresentation
bin100101010111111011…
…111101001010110100
310211120201202021112022
4211113323331022310
51124141242244000
630234022012312
72620313500424
oct452773751264
9124521667468
1040130040500
11160233a8430
12793b577098
133a26cb35c4
141d2997c484
15109d122585
hex957efd2b4

40130040500 has 192 divisors, whose sum is σ = 99349286400. Its totient is φ = 14026880000.

The previous prime is 40130040479. The next prime is 40130040521. The reversal of 40130040500 is 504003104.

It is an interprime number because it is at equal distance from previous prime (40130040479) and next prime (40130040521).

It is a super-2 number, since 2×401300405002 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 49604096 + ... + 49604904.

It is an arithmetic number, because the mean of its divisors is an integer number (517444200).

Almost surely, 240130040500 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 40130040500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (49674643200).

40130040500 is an abundant number, since it is smaller than the sum of its proper divisors (59219245900).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

40130040500 is a wasteful number, since it uses less digits than its factorization.

40130040500 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1179 (or 1167 counting only the distinct ones).

The product of its (nonzero) digits is 240, while the sum is 17.

Adding to 40130040500 its reverse (504003104), we get a palindrome (40634043604).

The spelling of 40130040500 in words is "forty billion, one hundred thirty million, forty thousand, five hundred".