Base | Representation |
---|---|
bin | 10010010010100111100001… |
… | …01010011111101010000100 |
3 | 12021102012022002202210021220 |
4 | 21021103300222133222010 |
5 | 20232444341011300200 |
6 | 221313441035040340 |
7 | 11320644263052021 |
oct | 1111236052375204 |
9 | 167365262683256 |
10 | 40222111431300 |
11 | 118a8113350937 |
12 | 46173938a00b0 |
13 | 1959c0c8525a6 |
14 | 9d0a91066548 |
15 | 49b4094814a0 |
hex | 2494f0a9fa84 |
40222111431300 has 72 divisors (see below), whose sum is σ = 120388940448000. Its totient is φ = 10356037883520.
The previous prime is 40222111431247. The next prime is 40222111431319. The reversal of 40222111431300 is 313411122204.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2311606900 + ... + 2311624299.
Almost surely, 240222111431300 is an apocalyptic number.
It is an amenable number.
40222111431300 is an abundant number, since it is smaller than the sum of its proper divisors (80166829016700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
40222111431300 is a wasteful number, since it uses less digits than its factorization.
40222111431300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4623231245 (or 4623231238 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 40222111431300 its reverse (313411122204), we get a palindrome (40535522553504).
The spelling of 40222111431300 in words is "forty trillion, two hundred twenty-two billion, one hundred eleven million, four hundred thirty-one thousand, three hundred".
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