411013434132 has 54 divisors (see below), whose sum is σ = 1208575222218. Its totient is φ = 117432409248.

The previous prime is 411013434113. The next prime is 411013434137. The reversal of 411013434132 is 231434310114.

411013434132 is a `hidden beast` number, since 4 + 110 + 134 + 3 + 413 + 2 = 666.

It can be written as a sum of positive squares in only one way, i.e., 211199070096 + 199814364036 = 459564^2 + 447006^2 .

It is a junction number, because it is equal to n+sod(n) for n = 411013434096 and 411013434105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (411013434137) by changing a digit.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 116498643 + ... + 116502170.

Almost surely, 2^411013434132 is an apocalyptic number.

411013434132 is a gapful number since it is divisible by the number (42) formed by its first and last digit.

It is an amenable number.

411013434132 is an abundant number, since it is smaller than the sum of its proper divisors (797561788086).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

411013434132 is a wasteful number, since it uses less digits than its factorization.

411013434132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 233000837 (or 233000825 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 411013434132 its reverse (231434310114), we get a palindrome (642447744246).

The spelling of 411013434132 in words is "four hundred eleven billion, thirteen million, four hundred thirty-four thousand, one hundred thirty-two".