Base | Representation |
---|---|
bin | 10010101101000100011110… |
… | …11011101000010100110000 |
3 | 12101122002100000211011012222 |
4 | 21112202033123220110300 |
5 | 20342342303340231230 |
6 | 223251154314340212 |
7 | 11443421564524235 |
oct | 1126421733502460 |
9 | 171562300734188 |
10 | 41131013211440 |
11 | 12118623746919 |
12 | 474357112a668 |
13 | 19c483a61c509 |
14 | a22a747b778c |
15 | 4b4da32376e5 |
hex | 25688f6e8530 |
41131013211440 has 40 divisors (see below), whose sum is σ = 95931276456240. Its totient is φ = 16400504942336.
The previous prime is 41131013211427. The next prime is 41131013211499. The reversal of 41131013211440 is 4411231013114.
It is a tau number, because it is divible by the number of its divisors (40).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 810917330 + ... + 810968049.
It is an arithmetic number, because the mean of its divisors is an integer number (2398281911406).
Almost surely, 241131013211440 is an apocalyptic number.
41131013211440 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
41131013211440 is an abundant number, since it is smaller than the sum of its proper divisors (54800263244800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41131013211440 is a wasteful number, since it uses less digits than its factorization.
41131013211440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1621885709 (or 1621885703 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 26.
Adding to 41131013211440 its reverse (4411231013114), we get a palindrome (45542244224554).
The spelling of 41131013211440 in words is "forty-one trillion, one hundred thirty-one billion, thirteen million, two hundred eleven thousand, four hundred forty".
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