Base | Representation |
---|---|
bin | 111011110110100111111… |
… | …111011010010100100111 |
3 | 112120012122011021201021010 |
4 | 323312213333122110213 |
5 | 1014342113120321411 |
6 | 12425311044553303 |
7 | 603106335111636 |
oct | 73664777322447 |
9 | 15505564251233 |
10 | 4113102120231 |
11 | 13463a1a11605 |
12 | 5651916b2833 |
13 | 23ab2cbb3730 |
14 | 10310a50d51d |
15 | 71ed05b97a6 |
hex | 3bda7fda527 |
4113102120231 has 32 divisors (see below), whose sum is σ = 6263606059200. Its totient is φ = 2378362742784.
The previous prime is 4113102120209. The next prime is 4113102120247. The reversal of 4113102120231 is 1320212013114.
It is not a de Polignac number, because 4113102120231 - 225 = 4113068565799 is a prime.
It is a super-2 number, since 2×41131021202312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4113102120198 and 4113102120207.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113102120251) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4653756 + ... + 5466593.
It is an arithmetic number, because the mean of its divisors is an integer number (195737689350).
Almost surely, 24113102120231 is an apocalyptic number.
4113102120231 is a deficient number, since it is larger than the sum of its proper divisors (2150503938969).
4113102120231 is a wasteful number, since it uses less digits than its factorization.
4113102120231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10120995.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 4113102120231 its reverse (1320212013114), we get a palindrome (5433314133345).
The spelling of 4113102120231 in words is "four trillion, one hundred thirteen billion, one hundred two million, one hundred twenty thousand, two hundred thirty-one".
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