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41133012101 is a prime number
BaseRepresentation
bin100110010011101101…
…111111010010000101
310221011122000111220122
4212103231333102011
51133220022341401
630521331111325
72654212556036
oct462355772205
9127148014818
1041133012101
1116498570885
127b7b442545
133b56a2121c
141dc2c60a8d
15110b1de21b
hex993b7f485

41133012101 has 2 divisors, whose sum is σ = 41133012102. Its totient is φ = 41133012100.

The previous prime is 41133012029. The next prime is 41133012103. The reversal of 41133012101 is 10121033114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28894900225 + 12238111876 = 169985^2 + 110626^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41133012101 is a prime.

Together with 41133012103, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 41133012101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41133012103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20566506050 + 20566506051.

It is an arithmetic number, because the mean of its divisors is an integer number (20566506051).

Almost surely, 241133012101 is an apocalyptic number.

It is an amenable number.

41133012101 is a deficient number, since it is larger than the sum of its proper divisors (1).

41133012101 is an equidigital number, since it uses as much as digits as its factorization.

41133012101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 41133012101 its reverse (10121033114), we get a palindrome (51254045215).

The spelling of 41133012101 in words is "forty-one billion, one hundred thirty-three million, twelve thousand, one hundred one".