Base | Representation |
---|---|
bin | 10010101101101010010110… |
… | …01001101101110010110101 |
3 | 12101201000210210222001220000 |
4 | 21112311023021231302311 |
5 | 20343210422140013140 |
6 | 223304355445501513 |
7 | 11445041425610160 |
oct | 1126651311556265 |
9 | 171630723861800 |
10 | 41151342501045 |
11 | 12126206035007 |
12 | 47474a5411899 |
13 | 19c672a2ab76a |
14 | a23a426d8ad7 |
15 | 4b5692d4aa30 |
hex | 256d4b26dcb5 |
41151342501045 has 80 divisors (see below), whose sum is σ = 84379071541248. Its totient is φ = 18795696710400.
The previous prime is 41151342501023. The next prime is 41151342501161. The reversal of 41151342501045 is 54010524315114.
41151342501045 is a `hidden beast` number, since 4 + 1 + 1 + 513 + 42 + 50 + 10 + 45 = 666.
It is not a de Polignac number, because 41151342501045 - 211 = 41151342498997 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 3042504 + ... + 9568673.
Almost surely, 241151342501045 is an apocalyptic number.
41151342501045 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
It is an amenable number.
41151342501045 is an abundant number, since it is smaller than the sum of its proper divisors (43227729040203).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41151342501045 is a wasteful number, since it uses less digits than its factorization.
41151342501045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12612352 (or 12612343 counting only the distinct ones).
The product of its (nonzero) digits is 48000, while the sum is 36.
Adding to 41151342501045 its reverse (54010524315114), we get a palindrome (95161866816159).
The spelling of 41151342501045 in words is "forty-one trillion, one hundred fifty-one billion, three hundred forty-two million, five hundred one thousand, forty-five".
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