Base | Representation |
---|---|
bin | 111011111010011001111… |
… | …010111000110001010100 |
3 | 112120121010000211012200201 |
4 | 323322121322320301110 |
5 | 1014423421210124000 |
6 | 12431221521150244 |
7 | 603312042152263 |
oct | 73723172706124 |
9 | 15517100735621 |
10 | 4117161020500 |
11 | 1348095075440 |
12 | 565b24a8b384 |
13 | 23b328a88678 |
14 | 1033b35d65da |
15 | 7216bac696a |
hex | 3be99eb8c54 |
4117161020500 has 192 divisors, whose sum is σ = 9915845651712. Its totient is φ = 1480920000000.
The previous prime is 4117161020471. The next prime is 4117161020519. The reversal of 4117161020500 is 50201617114.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 717147630 + ... + 717153370.
It is an arithmetic number, because the mean of its divisors is an integer number (51645029436).
Almost surely, 24117161020500 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 4117161020500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4957922825856).
4117161020500 is an abundant number, since it is smaller than the sum of its proper divisors (5798684631212).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4117161020500 is a wasteful number, since it uses less digits than its factorization.
4117161020500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7163 (or 7151 counting only the distinct ones).
The product of its (nonzero) digits is 1680, while the sum is 28.
Adding to 4117161020500 its reverse (50201617114), we get a palindrome (4167362637614).
The spelling of 4117161020500 in words is "four trillion, one hundred seventeen billion, one hundred sixty-one million, twenty thousand, five hundred".
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