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412132013300 = 225271259467641
BaseRepresentation
bin1011111111101001111…
…10110111010011110100
31110101210012002111112202
411333310332313103310
523223021243411200
6513155243204032
741530005212120
oct5776476672364
91411705074482
10412132013300
11149869860577
1267a5a216618
132cb2cc44b37
1415d39546580
15aac1a441d5
hex5ff4fb74f4

412132013300 has 72 divisors (see below), whose sum is σ = 1022901405120. Its totient is φ = 141189868800.

The previous prime is 412132013291. The next prime is 412132013309. The reversal of 412132013300 is 3310231214.

It is an interprime number because it is at equal distance from previous prime (412132013291) and next prime (412132013309).

It is a super-2 number, since 2×4121320133002 (a number of 24 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (412132013309) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 647480 + ... + 1115120.

It is an arithmetic number, because the mean of its divisors is an integer number (14206963960).

Almost surely, 2412132013300 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 412132013300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (511450702560).

412132013300 is an abundant number, since it is smaller than the sum of its proper divisors (610769391820).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

412132013300 is a wasteful number, since it uses less digits than its factorization.

412132013300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 468921 (or 468914 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 412132013300 its reverse (3310231214), we get a palindrome (415442244514).

The spelling of 412132013300 in words is "four hundred twelve billion, one hundred thirty-two million, thirteen thousand, three hundred".

Divisors: 1 2 4 5 7 10 14 20 25 28 35 50 70 100 140 175 350 700 1259 2518 5036 6295 8813 12590 17626 25180 31475 35252 44065 62950 88130 125900 176260 220325 440650 467641 881300 935282 1870564 2338205 3273487 4676410 6546974 9352820 11691025 13093948 16367435 23382050 32734870 46764100 65469740 81837175 163674350 327348700 588760019 1177520038 2355040076 2943800095 4121320133 5887600190 8242640266 11775200380 14719000475 16485280532 20606600665 29438000950 41213201330 58876001900 82426402660 103033003325 206066006650 412132013300