Base | Representation |
---|---|
bin | 10010110001111111111000… |
… | …10011000110001100001000 |
3 | 12102020021101221110210010110 |
4 | 21120333330103012030020 |
5 | 20403131100403244220 |
6 | 223501041004314320 |
7 | 11461565003516565 |
oct | 1130777423061410 |
9 | 172207357423113 |
10 | 41300343415560 |
11 | 12183417184479 |
12 | 47703495429a0 |
13 | 1a077b4881078 |
14 | a2ad394d986c |
15 | 4b94b3d79be0 |
hex | 258ffc4c6308 |
41300343415560 has 128 divisors (see below), whose sum is σ = 126925822920960. Its totient is φ = 10744566374400.
The previous prime is 41300343415553. The next prime is 41300343415631. The reversal of 41300343415560 is 6551434300314.
It is a super-2 number, since 2×413003434155602 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 375946240 + ... + 376056080.
It is an arithmetic number, because the mean of its divisors is an integer number (991607991570).
Almost surely, 241300343415560 is an apocalyptic number.
41300343415560 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
41300343415560 is an abundant number, since it is smaller than the sum of its proper divisors (85625479505400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41300343415560 is a wasteful number, since it uses less digits than its factorization.
41300343415560 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 186319 (or 186315 counting only the distinct ones).
The product of its (nonzero) digits is 259200, while the sum is 39.
Adding to 41300343415560 its reverse (6551434300314), we get a palindrome (47851777715874).
The spelling of 41300343415560 in words is "forty-one trillion, three hundred billion, three hundred forty-three million, four hundred fifteen thousand, five hundred sixty".
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