Base | Representation |
---|---|
bin | 111100000110011001101… |
… | …001010010101100110000 |
3 | 112121211100200100201012222 |
4 | 330012121221102230300 |
5 | 1020131311033410000 |
6 | 12441151554340212 |
7 | 604246162622564 |
oct | 74063151225460 |
9 | 15554320321188 |
10 | 4130041310000 |
11 | 13525a47165a1 |
12 | 56851a58a668 |
13 | 23c5cc405148 |
14 | 103c760bd6a4 |
15 | 7267277da85 |
hex | 3c199a52b30 |
4130041310000 has 100 divisors (see below), whose sum is σ = 10002973180200. Its totient is φ = 1651400256000.
The previous prime is 4130041309991. The next prime is 4130041310051. The reversal of 4130041310000 is 131400314.
It is a tau number, because it is divible by the number of its divisors (100).
It is a super-2 number, since 2×41300413100002 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 27214331 + ... + 27365669.
It is an arithmetic number, because the mean of its divisors is an integer number (100029731802).
Almost surely, 24130041310000 is an apocalyptic number.
4130041310000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 4130041310000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5001486590100).
4130041310000 is an abundant number, since it is smaller than the sum of its proper divisors (5872931870200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4130041310000 is a wasteful number, since it uses less digits than its factorization.
4130041310000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 154096 (or 154075 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 4130041310000 its reverse (131400314), we get a palindrome (4130172710314).
The spelling of 4130041310000 in words is "four trillion, one hundred thirty billion, forty-one million, three hundred ten thousand".
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