4300001130040 has 128 divisors (see below), whose sum is σ = 12342860766720. Its totient is φ = 1309091212800.

The previous prime is 4300001130013. The next prime is 4300001130049. The reversal of 4300001130040 is 400311000034.

4300001130040 is a modest number, since divided by 1130040 gives 43000 as remainder.

It is a junction number, because it is equal to n+sod(n) for n = 4300001129996 and 4300001130023.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4300001130049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16101331 + ... + 16366210.

It is an arithmetic number, because the mean of its divisors is an integer number (96428599740).

Almost surely, 2^{4300001130040} is an apocalyptic number.

4300001130040 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

4300001130040 is an abundant number, since it is smaller than the sum of its proper divisors (8042859636680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4300001130040 is a wasteful number, since it uses less digits than its factorization.

4300001130040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32467613 (or 32467609 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 4300001130040 its reverse (400311000034), we get a palindrome (4700312130074).

The spelling of 4300001130040 in words is "four trillion, three hundred billion, one million, one hundred thirty thousand, forty".