4301125141238 has 32 divisors (see below), whose sum is σ = 6752543616000. Its totient is φ = 2052373500000.

The previous prime is 4301125141193. The next prime is 4301125141279. The reversal of 4301125141238 is 8321415211034.

It is a junction number, because it is equal to n+sod(n) for n = 4301125141198 and 4301125141207.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 203513 + ... + 2940011.

It is an arithmetic number, because the mean of its divisors is an integer number (211016988000).

Almost surely, 2^{4301125141238} is an apocalyptic number.

4301125141238 is a deficient number, since it is larger than the sum of its proper divisors (2451418474762).

4301125141238 is a wasteful number, since it uses less digits than its factorization.

4301125141238 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2736884.

The product of its (nonzero) digits is 23040, while the sum is 35.

The spelling of 4301125141238 in words is "four trillion, three hundred one billion, one hundred twenty-five million, one hundred forty-one thousand, two hundred thirty-eight".