4302053141 has 2 divisors, whose sum is σ = 4302053142. Its totient is φ = 4302053140.

The previous prime is 4302053113. The next prime is 4302053143. The reversal of 4302053141 is 1413502034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4302048100 + 5041 = 65590^2 + 71^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4302053141 is a prime.

It is a super-2 number, since 2×4302053141² = 37015322455975931762, which contains 22 as substring.

Together with 4302053143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4302053143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2151026570 + 2151026571.

It is an arithmetic number, because the mean of its divisors is an integer number (2151026571).

Almost surely, 2^4302053141 is an apocalyptic number.

It is an amenable number.

4302053141 is a deficient number, since it is larger than the sum of its proper divisors (1).

4302053141 is an equidigital number, since it uses as much as digits as its factorization.

4302053141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 4302053141 is about 65590.0384281028. The cubic root of 4302053141 is about 1626.3921029797.

Adding to 4302053141 its reverse (1413502034), we get a palindrome (5715555175).

The spelling of 4302053141 in words is "four billion, three hundred two million, fifty-three thousand, one hundred forty-one".