Base | Representation |
---|---|
bin | 101000000101100111… |
… | …111111000110101011 |
3 | 11010002210221211220121 |
4 | 220011213333012223 |
5 | 1201123233304011 |
6 | 31435115104111 |
7 | 3052446212200 |
oct | 500547770653 |
9 | 133083854817 |
10 | 43044041131 |
11 | 1728926a213 |
12 | 8413442037 |
13 | 409c916b30 |
14 | 2124999ca7 |
15 | 11bdd79e71 |
hex | a059ff1ab |
43044041131 has 72 divisors (see below), whose sum is σ = 58460426640. Its totient is φ = 31386144384.
The previous prime is 43044041099. The next prime is 43044041137. The reversal of 43044041131 is 13114044034.
It is not a de Polignac number, because 43044041131 - 25 = 43044041099 is a prime.
It is a super-2 number, since 2×430440411312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43044041096 and 43044041105.
It is not an unprimeable number, because it can be changed into a prime (43044041137) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 8505880 + ... + 8510938.
It is an arithmetic number, because the mean of its divisors is an integer number (811950370).
Almost surely, 243044041131 is an apocalyptic number.
43044041131 is a deficient number, since it is larger than the sum of its proper divisors (15416385509).
43044041131 is a wasteful number, since it uses less digits than its factorization.
43044041131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5161 (or 5135 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 43044041131 its reverse (13114044034), we get a palindrome (56158085165).
The spelling of 43044041131 in words is "forty-three billion, forty-four million, forty-one thousand, one hundred thirty-one".
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