431201121102133 has 4 divisors (see below), whose sum is σ = 431871729378208. Its totient is φ = 430530512826060.

The previous prime is 431201121102119. The next prime is 431201121102217. The reversal of 431201121102133 is 331201121102134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 431201121102133 - 2²⁵ = 431201087547701 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 431201121102098 and 431201121102107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (431201121100133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335304137073 + ... + 335304138358.

It is an arithmetic number, because the mean of its divisors is an integer number (107967932344552).

Almost surely, 2^{431201121102133} is an apocalyptic number.

It is an amenable number.

431201121102133 is a deficient number, since it is larger than the sum of its proper divisors (670608276075).

431201121102133 is an equidigital number, since it uses as much as digits as its factorization.

431201121102133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 670608276074.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 431201121102133 its reverse (331201121102134), we get a palindrome (762402242204267).

Subtracting from 431201121102133 its reverse (331201121102134), we obtain a palindrome (99999999999999).

The spelling of 431201121102133 in words is "four hundred thirty-one trillion, two hundred one billion, one hundred twenty-one million, one hundred two thousand, one hundred thirty-three".